Given a network that requires at most 60 usable hosts per subnet, which CIDR notation provides the smallest subnet mask?

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Study for the Information Systems Technician Second Class (IT2) Advancement Exam with our extensive set of flashcards and multiple-choice questions. Each question is accompanied by hints and thorough explanations. Enhance your knowledge and prepare for success!

Multiple Choice

Given a network that requires at most 60 usable hosts per subnet, which CIDR notation provides the smallest subnet mask?

Explanation:
Understanding how many usable hosts a subnet can support is determined by the number of host bits. Usable hosts per subnet = 2^n - 2, where n is the number of host bits. To accommodate up to 60 usable hosts, you need 2^n - 2 ≥ 60, so 2^n ≥ 62. The smallest n that works is 6, which corresponds to a /26 subnet (64 total addresses, 62 usable). A /27 would provide only 30 usable hosts, which is not enough. A /25 or /24 would provide more hosts than needed, so they aren’t the smallest solution. Therefore, the smallest suitable CIDR is /26.

Understanding how many usable hosts a subnet can support is determined by the number of host bits. Usable hosts per subnet = 2^n - 2, where n is the number of host bits.

To accommodate up to 60 usable hosts, you need 2^n - 2 ≥ 60, so 2^n ≥ 62. The smallest n that works is 6, which corresponds to a /26 subnet (64 total addresses, 62 usable).

A /27 would provide only 30 usable hosts, which is not enough. A /25 or /24 would provide more hosts than needed, so they aren’t the smallest solution. Therefore, the smallest suitable CIDR is /26.

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